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  1. what is the sum of all the two-digits numbers which when divided by 7 gives a remainder of 3 ?
    1. 94
    2. 676
    3. 696
    4. None of these
Correct Option: B

According to question,
First Two Digit Number, which is divided by 7 and give the remainder 3, will be 10.
Last Two Digit Number, which is divided by 7 and give the remainder 3, will be 94.
The common difference between two consecutive numbers will be 7.
This series will be like 10, 17, 21 ,............................ 94.
Here First Number a = 10, Last number tn = 94, Common Difference d = 7 ;
Using the Formula for Last Number tn = a + (n - 1) x d;
a + (n - 1) x d = tn
Put the value of a , d and tn in above equation.
⇒ 10 + (n - 1) x 7 = 94
⇒ 10 + 7n - 7 = 94
⇒ 7n + 3 = 94
⇒ 7n = 94 - 3 = 91
⇒ n = 91/7
n = 13
Using the formula for the sum of Arithmetic Progression.
Sn = n/2 [ First Number + Last Number ] ;
Put the value of n , First Number and Last Number, we will get,
Sn = 13/2 [ 10 + 94 ]
Sn = 104 x 13/2
Sn = 52 x 13
Sn = 676



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