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A pot is filled with alcohal. 80% of alcohal is replaced by the same quantity of water. This process is done three times. Find the percentage of alcohal in this mixture of alcohal and water.
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- 51.2%
- 29%
- 38%
- 49%
Correct Option: A
Let quantity of alcohal = 1000 L
Quantity of alcohal after 1st process = 80% of 1000 L = 800 L
Quantity of alcohol after 2nd process = 80% of 800 L = 640 L
Quantity of alcohol after 3rd process = 80% of 640 L = 512 L
∴ Required percentage = (512/1000) x 100 = 51.2%
