In how many difference ways can six players be arranged

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In how many difference ways can six players be arranged in a line such that two of them, Abhinav and Manjesh are never together ?

1. 120
2. 240
3. 360
4. 480

Correct Option: C

As, there are six players, so total ways in which they can be arranged = 6 ! ways
Also, two particular players,are never together.
∴ Required ways = 6!/2! = 360

Comments

DHARMENDRA PARMAR
June 21, 2018 Reply

I think the above answer is wrong.
because from 6! ways we can arrange 6 persons in a line.
wherein question it is said that two people would never together so what we will do is we will put abhinav and manjesh together.
so we can arrange the together persons in 5!2! ways.

so total number of ways in which abhinav and manjesh are never together is 6! - 5!2! = 480 which is option D.