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A father divided his property between his two sons A and B. A invests the amount at compound interest of 8% per annum and B invests the amount at 10% per annum simple interest. At the end of 2 yr, the interest received by B is ₹ 1336 more than the interest received by A. Find the share of A in the father's property of ₹ 25000. ?
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- ₹ 12000
- ₹ 13000
- ₹ 12500
- ₹ 10000
Correct Option: D
Suppose A gets ₹ P and B gets ₹ (25000 - P).
Interest received by A at the rate of 8% per annum CI
= P(1 + 8/100)2 - P
= P(27/25)2 - P
= 104P/625
Interest received by B at the rate of 10% per annum SI
= [(25000 - P) x 10 x 2]/100 = (25000 - P)/5
According to the question,
(25000 - P)/5 = 104P/(625 + 1336)
∴ P = 10000
