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If the HCF of two positive integers is 26. Then their LCM cannot be ?
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- 78
- 104
- 144
- 234
Correct Option: C
LCM of the number is always divisible by the HCF of the same numbers.
So, 78, 104 and 234 are all divisible by 26. Whereas, 144 is not divisible by 26.
Thus, 144 cannot be the LCM of the number whose HCF is 26.