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Direction: In each of the following question, there are two equations. you have to solve both equations and give answer.

  1. x2 - 8x + 15 = 0 ; y2 - 3y + 2 = 0
    1. If x > y
    2. If x ≥ y
    3. If x < y
    4. If x ≤ y
    5. If x = y or relation cannot be established
Correct Option: A

x2 - 8x + 15 = 0
⇒ x2 - 5x - 3x + 15 = 0
⇒ x(x - 5) -3(x - 5) = 0
⇒ (x - 5) (x - 3) = 0
∴ x = 5, 3
and y2 - 3y + 2 = 0
⇒ y2 - 2y - y + 2 = 0
⇒ y(y - 2) -1(y - 2) = 0
⇒ (y -2) (y - 1) = 0
⇒ y = 2, 1
∴ x > y



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