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If p and q are the roots of the equation x2 + px + q = 0, then
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- p = 1 and q = -2
- p = 0 and q = 1
- p = -2 and q = 0
- p = -2 and q = 1
Correct Option: A
Since, p and q are the roots of the equation x2 + px + q = 0
Then, p + q = - p
and pq = q
Now, pq = q
⇒ p = 1
Putting the value of p in p + q = - p, we get
1 + q = - 1
⇒ q = - 2
