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The quadrictic equation whose roots are 3 and -1, is
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- x2 - 4x + 3 = 0
- x2 - 2x - 3 = 0
- x2 + 2x - 3 = 0
- x2 + 4x + 3 = 0
Correct Option: B
Given that, the roots of the quadrictic equation are 3 and -1.
Let α = 3 and β = -1
Sum of roots = α + β = 3 - 1 = 2
Products of roots = α . β = (3) (-1) = -3
∴ Required quadric equation is
x2 - (α + β)x + α β = 0
⇒ x2 - (2)x + (-3) = 0
⇒ x2 - 2x - 3 = 0
