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  1. Find the value of a 3 + b 3 + c 3 - 3abc when a = 225, b = 226 , c = 227
    1. 2304
    2. 2430
    3. 2034
    4. 2340
Correct Option: C

We know that,
a3 + b3 + c3 - 3abc
= (a + b + c) 1/2 [(a - b) 2 + (b - c) 2 + (c - a) 2]
= (225 + 226 + 227) 1/2 [1 + 1 + 4]
= 678 x 3 = 2034


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