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From 4 officers and 8 Jawans in how many ways can 6 be chosen to include at least one officer?
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- 896
- 986
- 886
- 996
Correct Option: A
We may choose 1 officer and 5 jawans or 2 officers and 4 jawans ......... or 4 officers and 2 jawans.
So Required answer = [4C1 x 8C5] + [4C2 x 8C4] + [4C3 x 8C3] + [4C4 x 8C2]
= 224 + 420 + 224 + 28 = 896.