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A library has 'a' copies of one book, 'b' copies of each of two book, 'c' copies of each of three books and single copy of 'd' book. The number of ways in which these books can be distribute is ?
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- (a + b + c + d)! / (a! b! c!)
- (a + 2b + 3c + d)! / {a! (b!)2 (c!)3}
- (a + 2b + 3c + d )! / (a! b! c!)
- None of these
Correct Option: B
Total number of books = a + 2b + 3c + d . Since there are 'b' copies of each of two books, 'c' copies of each of three books and single copy of 'd' book.
Therefore, the total number of arrangements is = (a + 2b + 3c + d )! / {a! (b!)2 (c!)3}
