In a box carrying one dozen of oranges, one third have become

Home » Aptitude » Probability » Question

In a box carrying one dozen of oranges, one third have become bad. If 3 oranges are taken out from the box at random, what is the probability that at least one oranges out of the three oranges picked up is good ?

1. 1/55
2. 54/55
3. 45/55
4. 3/55

Correct Option: B

n(S) = ¹²C₃ = (12 x 11 x 10) / (3 x 2) = 2 x 11 x 10 = 220

No. of selecting of 3 oranges out of the total 12 orange = ⁴C₃ = 4
∴ n(E) = No. of desired selection of oranges = 220 - 4 = 216

∴ P(E) = n(E) / n(S) = 216 / 220 = 54/55