Control systems miscellaneous
- The asymptotes and the break point coincide at s = – 2. The transfer function can be—
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In option (C) and (D) both have centroid at s = – 2 in (C) break point is lies between 1 and 2 However in (D) break point lies at s = – 2.
Correct Option: D
In option (C) and (D) both have centroid at s = – 2 in (C) break point is lies between 1 and 2 However in (D) break point lies at s = – 2.
- System has phase margin φPM = 45°. The damping ratio ξ is—
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Given, φPM = 45°
ξ = ?ξ = tan φPM√cos φPM 2
= tan 45°√cos 45° 2 Correct Option: D
Given, φPM = 45°
ξ = ?ξ = tan φPM√cos φPM 2
= tan 45°√cos 45° 2
- The frequency at which the Nyquist diagram crosses the negative real axis is known as—
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The frequency at which the Nyquist diagram crosses the negative real axis is known as phase cross-over frequency.
Correct Option: B
The frequency at which the Nyquist diagram crosses the negative real axis is known as phase cross-over frequency.
- The frequency at which the Nyquist diagram cuts (– 1, 0) circle is known as—
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The frequency at which the Nyquist diagram cuts (–1, 0) circle is known as gain cross-over frequency.
Correct Option: A
The frequency at which the Nyquist diagram cuts (–1, 0) circle is known as gain cross-over frequency.
- NA
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The phase margin, φPM and damping ratio, ξ is related by equation
ξ = tan φPM√cos φPM 2
thus, from this relation we conclude that
● Phase margin φPM is directly proportional to damping ratio.
● When phase margin, is 0, damping ratio, ξ is 0.Correct Option: A
The phase margin, φPM and damping ratio, ξ is related by equation
ξ = tan φPM√cos φPM 2
thus, from this relation we conclude that
● Phase margin φPM is directly proportional to damping ratio.
● When phase margin, is 0, damping ratio, ξ is 0.
