Control systems miscellaneous
- The step error coefficient of a system G(s) = 1/(s + 6) (s + 1) with unity feedback is—
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Step error coefficient also called positional error coefficient i.e.,
Kp = s → 0Lim G(s)H(s)
= s → 0Lim 1/(s + 6) (s + 1)
= 1/6Correct Option: A
Step error coefficient also called positional error coefficient i.e.,
Kp = s → 0Lim G(s)H(s)
= s → 0Lim 1/(s + 6) (s + 1)
= 1/6
- A lead compensating network—
(i) improves response time
(ii) increases resonant frequency
(iii) stabilizes the system with low phase margin
(iv) enables moderate increase in gain without affecting stability The correct statements are—
-
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Refer synopsis.
Correct Option: A
Refer synopsis.
- In the signal flow graph of figure shown below y/x equal to—
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From figure y = 5 × 2 × x – 2 × 2 × y
or
y + 4y = 10x
or
5y = 10x
or
y/x = 2Correct Option: C
From figure y = 5 × 2 × x – 2 × 2 × y
or
y + 4y = 10x
or
5y = 10x
or
y/x = 2
- A certain linear time invariant system has the state and the output equations given below
x1 = 1 -1 x1 + 0 u x2 0 1 x2 1 y = [1 1] x1 x2
If X1(0) = 1,
X2(0) = – 1,
u (0) = 0
then | dy/dt |t = 0 is—
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From given data y = x1 + x2
y |t = 0 = 1 – 1
or
y |t = 0 = 0
or dy/dx| t = 0 = 0Correct Option: C
From given data y = x1 + x2
y |t = 0 = 1 – 1
or
y |t = 0 = 0
or dy/dx| t = 0 = 0
- Consider a unit feedback control system with open-loop transfer function
G (s) = K/ [s (s + 1)].
The steady state error of the system due to a unit step input is—
-
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ess = s → 0Lim sE(s)
= s → 0Lims. s.R(s) 1 + (K/s(s+1))1
= H(s) = 1 and if r(t) = u(t)
then R(s) = 1/s= s → 0Lim s(s + 1) s(s + 1) + K
= 0Correct Option: A
ess = s → 0Lim sE(s)
= s → 0Lims. s.R(s) 1 + (K/s(s+1))1
= H(s) = 1 and if r(t) = u(t)
then R(s) = 1/s= s → 0Lim s(s + 1) s(s + 1) + K
= 0