Control systems miscellaneous
- The transfer function for the Bode plot given below is–
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One pole at ω = 5 i.e., (1 + s/5)
Two pole at ω = 40 i.e., (1 + s/40)2
One pole at ω = 100 i.e., (1 + s/100)
and 20 log10 K = 100
or
K = 105
Now,T.F = 105 (1+s/5)(1+s/40)2(1+s/100) Correct Option: C
One pole at ω = 5 i.e., (1 + s/5)
Two pole at ω = 40 i.e., (1 + s/40)2
One pole at ω = 100 i.e., (1 + s/100)
and 20 log10 K = 100
or
K = 105
Now,T.F = 105 (1+s/5)(1+s/40)2(1+s/100)
- Which one of the following system is completely state controllable?
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Try yourself
Correct Option: A
Try yourself
- The signal flow diagram of a system is shown in the given figure. The number of forward paths and the number of pairs of non-touching loops are respectively—
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The forward paths are
— A B C D E F
— A B D E F
— A B E F i.e., 3
The loop B C B and D D are non-touching loop
Hence alternative (A) is the correct choice.Correct Option: A
The forward paths are
— A B C D E F
— A B D E F
— A B E F i.e., 3
The loop B C B and D D are non-touching loop
Hence alternative (A) is the correct choice.
- The transfer function of a system is given by
G (jω) = K K < 1 (jω) (jω T + 1) T
Which one of the following is the Bode plot of this
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For better understanding refer synopsis.
Correct Option: C
For better understanding refer synopsis.
- The Nyquist plot of a open loop transfer function G (jω) H(jω) of a system encloses the (– 1, j0) point, the gain margin of the system is—
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Gain margin of the system for which Nyquist plot of a loop transfer function G(jω) H(jω) encloses (– 1 + j0) point, makes the system unstable. Hence obviously the gain margin of the systems less than zero.
Correct Option: A
Gain margin of the system for which Nyquist plot of a loop transfer function G(jω) H(jω) encloses (– 1 + j0) point, makes the system unstable. Hence obviously the gain margin of the systems less than zero.