Control systems miscellaneous


Control systems miscellaneous

  1. The transfer function for the Bode plot given below is–











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    One pole at ω = 5 i.e., (1 + s/5)
    Two pole at ω = 40 i.e., (1 + s/40)2
    One pole at ω = 100 i.e., (1 + s/100)
    and 20 log10 K = 100
    or
    K = 105
    Now,

    T.F =
    105
    (1+s/5)(1+s/40)2(1+s/100)


    Correct Option: C

    One pole at ω = 5 i.e., (1 + s/5)
    Two pole at ω = 40 i.e., (1 + s/40)2
    One pole at ω = 100 i.e., (1 + s/100)
    and 20 log10 K = 100
    or
    K = 105
    Now,

    T.F =
    105
    (1+s/5)(1+s/40)2(1+s/100)



  1. Which one of the following system is completely state controllable?









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    Try yourself

    Correct Option: A

    Try yourself



  1. The signal flow diagram of a system is shown in the given figure. The number of forward paths and the number of pairs of non-touching loops are respectively—











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    The forward paths are
    — A B C D E F
    — A B D E F
    — A B E F i.e., 3
    The loop B C B and D D are non-touching loop
    Hence alternative (A) is the correct choice.


    Correct Option: A

    The forward paths are
    — A B C D E F
    — A B D E F
    — A B E F i.e., 3
    The loop B C B and D D are non-touching loop
    Hence alternative (A) is the correct choice.



  1. The transfer function of a system is given by
    G (jω) =
    K
    K <
    1
    (jω) (jω T + 1)T

    Which one of the following is the Bode plot of this









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    For better understanding refer synopsis.

    Correct Option: C

    For better understanding refer synopsis.



  1. The Nyquist plot of a open loop transfer function G (jω) H(jω) of a system encloses the (– 1, j0) point, the gain margin of the system is—









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    Gain margin of the system for which Nyquist plot of a loop transfer function G(jω) H(jω) encloses (– 1 + j0) point, makes the system unstable. Hence obviously the gain margin of the systems less than zero.

    Correct Option: A

    Gain margin of the system for which Nyquist plot of a loop transfer function G(jω) H(jω) encloses (– 1 + j0) point, makes the system unstable. Hence obviously the gain margin of the systems less than zero.