Control systems miscellaneous


Control systems miscellaneous

  1. NA









  1. View Hint View Answer Discuss in Forum

    The phase margin, φPM and damping ratio, ξ is related by equation

    ξ =
    tan φPMcos φPM
    2

    thus, from this relation we conclude that
    ● Phase margin φPM is directly proportional to damping ratio.
    ● When phase margin, is 0, damping ratio, ξ is 0.

    Correct Option: A

    The phase margin, φPM and damping ratio, ξ is related by equation

    ξ =
    tan φPMcos φPM
    2

    thus, from this relation we conclude that
    ● Phase margin φPM is directly proportional to damping ratio.
    ● When phase margin, is 0, damping ratio, ξ is 0.


  1. The frequency at which the Nyquist diagram crosses the negative real axis is known as—









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    The frequency at which the Nyquist diagram crosses the negative real axis is known as phase cross-over frequency.

    Correct Option: B

    The frequency at which the Nyquist diagram crosses the negative real axis is known as phase cross-over frequency.



  1. The frequency at which the Nyquist diagram cuts (– 1, 0) circle is known as—









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    The frequency at which the Nyquist diagram cuts (–1, 0) circle is known as gain cross-over frequency.

    Correct Option: A

    The frequency at which the Nyquist diagram cuts (–1, 0) circle is known as gain cross-over frequency.


  1. System has phase margin φPM = 45°. The damping ratio ξ is—









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    Given, φPM = 45°
    ξ = ?

    ξ =
    tan φPMcos φPM
    2

    =
    tan 45°√cos 45°
    2

    Correct Option: D

    Given, φPM = 45°
    ξ = ?

    ξ =
    tan φPMcos φPM
    2

    =
    tan 45°√cos 45°
    2



  1. Match List-I with List-II and select the correct answer using the codes given below the lists:











  1. View Hint View Answer Discuss in Forum

    K1s + K2
    =
    K1s
    +
    K2
    → PD—controller
    K3K3K3

    K1s2 + K2s + K3
    =
    K1s
    +
    K2
    +
    K3
    1
    → PID—controller
    K4sK4K4K4s

    K1s + K2
    =
    K1
    +
    K2
    → PI—controller
    K3sK3K3

    K1s K2s
    =
    K1
    → P—controller
    K2sK2

    Hence alternative (A) is the correct choice.

    Correct Option: A

    K1s + K2
    =
    K1s
    +
    K2
    → PD—controller
    K3K3K3

    K1s2 + K2s + K3
    =
    K1s
    +
    K2
    +
    K3
    1
    → PID—controller
    K4sK4K4K4s

    K1s + K2
    =
    K1
    +
    K2
    → PI—controller
    K3sK3K3

    K1s K2s
    =
    K1
    → P—controller
    K2sK2

    Hence alternative (A) is the correct choice.