From the given Bode-plot H(s) has a pole at ω = 0 and ω = 0·05
and zero at ω = 0·1.
Hence H(s) can be given as

H(s) =	K(s + 0·1)
	s(s + 0·05)

By plot,
20 log₁₀ |H(j0·01)| = 60
or
|H(j0·01)| = 10³ = 1000.
or

∣	2K(0·1 + j0·01)	∣ = 1000
	j0·01(0·05 + j0·01)

or

K × 0·1	= 1000
0·01 × 0·05

or

K =	1000 × 0·01 × 0·05	= 5
	0·1

Therefore,

H(s) =	5(s + 0·1)
	s(s + 0·05)

Hence alternative (D) is the correct choice.

Correct Option: D

From the given Bode-plot H(s) has a pole at ω = 0 and ω = 0·05
and zero at ω = 0·1.
Hence H(s) can be given as

H(s) =	K(s + 0·1)
	s(s + 0·05)

By plot,
20 log₁₀ |H(j0·01)| = 60
or
|H(j0·01)| = 10³ = 1000.
or

∣	2K(0·1 + j0·01)	∣ = 1000
	j0·01(0·05 + j0·01)

or

K × 0·1	= 1000
0·01 × 0·05

or

K =	1000 × 0·01 × 0·05	= 5
	0·1

Therefore,

H(s) =	5(s + 0·1)
	s(s + 0·05)

Hence alternative (D) is the correct choice.