56. The value of ω1 for the data given is Q. 251–
    

1. 1. 4 rad/sec
      

   
   
   

   2. 2 rad/sec
      

   
   
   

   3. 5 rad/sec
      

   
   
   

   4. 1 rad/sec

   
   
   

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1. View Hint View Answer Discuss in Forum

   From figure given in solution 251
   

   log10	8	=	24.1
   	ω1		40

   
   or
   ω₁ = 2 rad/sec

   Correct Option: B

   From figure given in solution 251
   

   log10	8	=	24.1
   	ω1		40

   
   or
   ω₁ = 2 rad/sec

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57. The value of ω2 for the data given in Q. 251–
    

1. 1. 8 rad/sec
      

   
   
   

   2. 16 rad/sec
      

   
   
   

   3. 2 rad/sec
      

   
   
   

   4. 4 rad/sec

   
   
   

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1. View Hint View Answer Discuss in Forum

   40 = log	12·05 + 24·1
   	log10(ω2/ω1)

   
   or
   

   log10		ω2		=	36·15
   		ω1			40

   
   or
   

   log10 =		ω2		=	36·15
   		2			40

   
   or
   ω₂ = 16·02 rad/sec

   Correct Option: B

   40 = log	12·05 + 24·1
   	log10(ω2/ω1)

   
   or
   

   log10		ω2		=	36·15
   		ω1			40

   
   or
   

   log10 =		ω2		=	36·15
   		2			40

   
   or
   ω₂ = 16·02 rad/sec

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58. The value of ω3 for the data given in Q. 251–
    

1. 1. 40 rad/sec
      

   
   
   

   2. 20 rad/sec
      

   
   
   

   3. 32 rad/sec
      

   
   
   

   4. None of these

   
   
   

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1. View Hint View Answer Discuss in Forum

   (20·05 – 12·05)	= 20
   log(ω3/ω1)

   
   or
   

   log		ω3		=	8
   		ω1			20

   
   or
   

   log		ω3		= 0.4
   		16

   
   or
   ω₃ = 40·19

   Correct Option: A

   (20·05 – 12·05)	= 20
   log(ω3/ω1)

   
   or
   

   log		ω3		=	8
   		ω1			20

   
   or
   

   log		ω3		= 0.4
   		16

   
   or
   ω₃ = 40·19

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59. The gain factor K for the data given in Q. 251–
    

1. 1. 16
      

   
   
   

   2. 32
      

   
   
   

   3. 8
      

   
   
   

   4. 64

   
   
   

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1. View Hint View Answer Discuss in Forum

   20 log	K	|s = ω1 = 24·1
   	s

   
   or
   

   log	K	|s = 2 =	24·1
   	2		20

   
   or
   

   K	|s = 2 = 101.2
   2

   
   or
   K = 32

   Correct Option: B

   20 log	K	|s = ω1 = 24·1
   	s

   
   or
   

   log	K	|s = 2 =	24·1
   	2		20

   
   or
   

   K	|s = 2 = 101.2
   2

   
   or
   K = 32

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60. Find the value of K for the given Bode plot–
    
    
    
    

1. 1. 80
      

   
   
   

   2. 40
      

   
   
   

   3. 20
      

   
   
   

   4. 10

   
   
   

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1. View Hint View Answer Discuss in Forum

   Since there are 2 zeros at 0.
   20 log ks²|_{s = 0.5} = 26
   or
   20 log ks²|_{s = 0.5} = 10^26/20
   or
   

   K =	19.95	=	19.95	= 79.81 ≈ 80
   	s2		(·25)2

   
   

   Correct Option: A

   Since there are 2 zeros at 0.
   20 log ks²|_{s = 0.5} = 26
   or
   20 log ks²|_{s = 0.5} = 10^26/20
   or
   

   K =	19.95	=	19.95	= 79.81 ≈ 80
   	s2		(·25)2

   
   

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