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The system having the Bode magnitude plot shown in figure has the transfer function—
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60 (s + 0·01)(s + 0·1) s2(s + 0·05)2
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5(1 + 10s) s(1 + 20s) -
8(s + 0·05) s(s + 0·1)(s + 1) -
5(s + 0·1) s(s + 0·05)
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Correct Option: D
From the given Bode-plot H(s) has a pole at ω = 0 and ω = 0·05
and zero at ω = 0·1.
Hence H(s) can be given as
H(s) = | |
s(s + 0·05) |
By plot,
20 log10 |H(j0·01)| = 60
or
|H(j0·01)| = 103 = 1000.
or
∣ | ∣ = 1000 | |
j0·01(0·05 + j0·01) |
or
= 1000 | |
0·01 × 0·05 |
or
K = | = 5 | |
0·1 |
Therefore,
H(s) = | |
s(s + 0·05) |
Hence alternative (D) is the correct choice.
