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The transfer function for the Bode plot given below is–
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105 (1+s/5)(1+s/40)(1+s/100) -
106 (1+s/5)(1+s/40)2(1+s/100)
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105 (1+s/5)(1+s/40)2(1+s/100)
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106 (1+s/5)(1+s/40)(1+s/100)2
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Correct Option: C
One pole at ω = 5 i.e., (1 + s/5)
Two pole at ω = 40 i.e., (1 + s/40)2
One pole at ω = 100 i.e., (1 + s/100)
and 20 log10 K = 100
or
K = 105
Now,
| T.F = | |
| (1+s/5)(1+s/40)2(1+s/100) |
