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The asymptotes and the break point coincide at s = – 2. The transfer function can be—
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K(s + 2) (s + 1)(s + 2)
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K(s + 2) (s + 1)(s + 3)
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K (s + 1)(s + 2)(s + 3)
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K (s + 2)3
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Correct Option: D
In option (C) and (D) both have centroid at s = – 2 in (C) break point is lies between 1 and 2 However in (D) break point lies at s = – 2.
