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The second order system defined by
25 s2 + 5s + 25
is given a step input. The time taken for the output to settle within ± 2% of input is—
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- 1.2 sec
- 1.6 sec
- 2 sec
- 0.4 sec
- 1.2 sec
Correct Option: B
| Settling time = | for ± 2% of input | |
| ξωn |
from the given C.E. ⇒ s2 + 5s + 25 = 0
ω2n = 25
2ξ ωn = 5
| ξ = | = | = 0·5 | ||
| 2 × ωn | 2 × 5 |
| so, settling time = | = | = | |||
| ξωn | 0·5 × 5 | 2·5 |
= 1.6 sec.
