Square root and cube root
- Which of the following numbers, Where in some of the digit have been suppressed by Symbols, can possibly be the perfect square of a 3 digit odd number. ?
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The square of an odd number cannot have 4 as the unit digit. The square of a 3 digit number will have at least 5 digit and at the most 6 digits.
Correct Option: A
The square of an odd number cannot have 4 as the unit digit. The square of a 3 digit number will have at least 5 digit and at the most 6 digits. So. answer (A) is correct.
- Find the least number which when multiplied with 74088 will make it a perfect square.
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74088 = 2 x 2 x 2 x 3 x 3 x 3 x 7 x 7 x 7
Correct Option: A
74088 = 2 x 2 x 2 x 3 x 3 x 3 x 7 x 7 x 7
= (2x2) x (3x3) x (7x7) x (2x3x7)
Least number which should be multiplied to 74088 to make it a Perfect square = 2 x 3 x 7 = 42
- √(12 + √12 + √12 + ... = ?
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Let given expression = x
Then, √12 + x = xCorrect Option: B
Let given expression = x
Then, √12 + x = x
⇒ 12 + x = x2
⇒ x2 - x - 12 = 0
⇒ (x - 4) (x + 3) = 0
So, x = 4 (neglecting x = -3)
- If √1 + 27/169) = (1 + N/13). then N equals ?
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√1 + 27/169 = (1 + N/13)
∴ √196/169 = (1 + N/13)Correct Option: A
√1 + 27/169 = (1 + N/13)
∴ √196/169 = (1 + N/13)
⇒ 14/13 = (1 + N/13)
⇒ N/13 = (14/13 - 1 ) = 1/13
∴ N = 1
- √(1.21 x 0.9) / (1.1 x 0.11) = ?
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Given expression = √(121 x 9) / (11 x 11)
= √9Correct Option: B
Given expression = √(121 x 9) / (11 x 11)
= √9
= 3