Square root and cube root
-  250 / √? = 10
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                        View Hint View Answer Discuss in Forum Let 250 / √x = 10. 
 Then, √x= 250 / 10 = 25Correct Option: ALet 250 / √x = 10. 
 Then √x= 250 / 10 = 25
 ∴ x = 625
-  Find the cube root of 19683.
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                        View Hint View Answer Discuss in Forum In 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7. Correct Option: DIn 19683, 19 lies between 23 and 33, so left digit is 2 and 683 ends with 3, so right digit is 7. 
 thus 27 is a cube root of 19683.
-  √4/3 - √3/4 = ?
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                        View Hint View Answer Discuss in Forum √4/√3 - √3/√4 
 = 2/√3 - √3/2
 = (4 - 3)/2√3
 = 1/2√3Correct Option: A√4/√3 - √3/√4 
 = 2/√3 - √3/2
 = (4 - 3)/2√3
 = 1/2√3
-  If √2 = 1.4142, then the approximate value of 1/√2/9 is ?
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                        View Hint View Answer Discuss in Forum √2/9 
 = √2/√9
 = √2/3
 = 1.4142/3Correct Option: B√2/9 
 = √2/√9
 = √2/3
 = 1.4142/3
 ∴ 1/√2/9 = 0.4714
-  If √3 = 1.732, then the approximate value of 1/√3 is ?
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                        View Hint View Answer Discuss in Forum 1/√3 = 1/√3 x (√3 / √3) 
 = √3/3
 = 1.732 / 3Correct Option: C1/√3 = 1/√3 x (√3 / √3) 
 = √3/3
 = 1.732 / 3
 = 0.577
 
	