Ratio, Proportion
- In a school the ratio of boy and girls is 4 : 5 When 100 girls leave the school the ratio become 6 : 7. How many boys are there in the school ?
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Let number of boys = 4N and number of girls = 5N
Accounting to the question
4N / (5N - 100) = 6/7Correct Option: B
Let number of boys = 4N and number of girls = 5N
Accounting to the question
4N / (5N - 100) = 6/7
⇒ 28N = 6 ( 5N - 100 )
⇒ 28N = 30N - 600
⇒ 2N = 600
∴ N = 600/2 = 300
∴ Number of boys = 4N = 4 x 300 = 1200
- In a class the number of boys and girls is in the ratio of 4 : 5. If 10 more boys join the class, the ratio of numbers of boys and girls become 6 : 5. How many girls there in the class ?
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Let original number of boys = 4N and number of girls = 5N
According to the question
(4N + 10)/5N = 6/5Correct Option: C
Let original number of boys = 4N and number of girls = 5N
According to the question
(4N + 10)/5N = 6/5
⇒ 30N = 20N + 50
⇒ 10N = 50
∴ N = 50/10 = 5
∴ Number of girls = 5N = 5 x 5 = 25
- The total number of student in a school is 8670. If the number of boys in the school is 4545, then what will be the ratio of the total number of boys to the total number of girls in the school ?
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Total number of student = 8670
Total number of boys = 4545
∴ Total number of girls = 8670 - 4545 = 4125Correct Option: A
Total number of student = 8670
Total number of boys = 4545
∴ Total number of girls = 8670 - 4545 = 4125
∴ Required ratio = 4545 : 4125 = 303 : 275
- A truck covers a distance 640 km in 10 h. A car covers the same distance in 8 h. What is the respective ratio of speed of the truck to that of car ?
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Speed of truck 640/10 = 64 km/h
Speed of car = 640/8 = 80 km/hCorrect Option: C
Speed of truck 640/10 = 64 km/h
Speed of car = 640/8 = 80 km/h
So, the required ratio = 64/80 = 4/5 = 4 : 5
- A certain distance is covered at a certain speed. If half of this distance is covered in double the time, the ratio of the two speeds is
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Case I Speed = Distance/ Time
Case II Speed = (Distance/2) / (2 x Time) = Distance / (4 x Time)Correct Option: B
Case I Speed = Distance/ Time
Case II Speed = (Distance/2) / (2 x Time) = Distance / (4 x Time)
∴ Required ratio = 1/4 = 1:4