Problems on Ages
- The ratio of Mona's age to the age of her mother is 5 : 15. The difference of their ages is 24 years. The ratio of their ages After 3 years will be ?
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Let the age of Mona and her mother be 5x and 13x years respectively.
Then, (13x - 5x) = 24
⇒ x = 3Correct Option: C
Let the age of Mona and her mother be 5x and 13x years respectively.
Then, (13x - 5x) = 24
⇒ x = 3
So, their present ages are 15 years and 39 years
Ratio of their ages after 3 years = 18 : 42 = 3 : 7
- Shyam is 3 times as old as his son. After 10 years the sum of their ages will be 76 years. the respective ages of the father and the son are .... and .... years. ?
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Let son's age present age be x years .
∴ Father's present age = 3x years
Son's age 10 years hence = ( x + 10) years
Father's age 10 years hence = (3x + 10)
As per the condition ,
∵ ( x + 10) + (3x + 10) = 76Correct Option: A
Let son's age present age be x years .
∴ Father's present age = 3x years
Son's age 10 years hence = ( x + 10) years
Father's age 10 years hence = (3x + 10)
As per the condition ,
∵ ( x + 10) + (3x + 10) = 76
⇒ 4x = 56
∴ x = 14
∴ Son's present age = 14 years
Father's present age = 42 years
- If 6 years are subtracted from the present age of Randheer and the remainder is divided by 18 than the present age of his grandson Anup is obtained. If Anup is 2 years younger to mahesh whose age 5 years, then what's the age of Randheer ?
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∵ Anup's age = (5 - 2) years = 3 years
Let Randheer's age be x years.
Then, (x - 6)/18 = 3Correct Option: D
∵ Anup's age = (5 - 2) years = 3 years
Let Randheer's age be x years.
Then, (x - 6)/18 = 3
⇒ x = 54 + 6 = 60
- If the two digits of the age of Mr. Manoj are reversed then the new age so obtained is the age of his wife. 1/11 of the sum of their ages is equal to the difference between their ages. If Mr. Manoj is elder than his wife then find the difference their ages ?
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Let the age of Mr Manoj be (10y + y) yrs.
∴ His wife's age = (10y + x ) years
Then, ((10x + y + 10y + x) / 11 = 10x + y -10y-x
⇒ x + y = 9x - 9y
⇒ 8x = 10y
⇒ x/y = 5/4
∴ x = 5 and y =4 (because any other multiple of 5 will make x of two digits).
∴ Diff. = (10x + y) - (10y - x)
= 9x - 9y
= 9(x-y)
= 9(5-4)
= 9 yrs.Correct Option: C
Let the age of Mr Manoj be (10y + y) yrs.
∴ His wife's age = (10y + x ) years
Then, ((10x + y + 10y + x) / 11 = 10x + y -10y-x
⇒ x + y = 9x - 9y
⇒ 8x = 10y
⇒ x/y = 5/4
∴ x = 5 and y =4 (because any other multiple of 5 will make x of two digits).
∴ Diff. = (10x + y) - (10y - x)
= 9x - 9y
= 9(x-y)
= 9(5-4)
= 9 yrs.
- A father's age is three times the sum of the ages of his two children but 20 years hence his age will be equal to the sum of their ages. Then the father's age is ?
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Let the present age of father be x years and the sum of present ages of 2 sons be y years.
∵ x = 3y ...(i)
⇒ (x + 20) = (y + 20 + 20) ...(ii) [20 will be added twice as for 2 children]Correct Option: A
Let the present age of father be x years and the sum of present ages of 2 sons be y years.
∵ x = 3y ...(i)
⇒ (x + 20) = (y + 20 + 20) ...(ii) [20 will be added twice as for 2 children]
Solving (i) and (ii), we get
x = 30 years
