Nuclei

Nuclei

Easy Questions

Modern Physics

Dual Nature of Radiation and Matter
Atoms
Nuclei
Semiconductor Electronics : Materials, Devices and Simple Circuits
  1. ​In the reaction, 1H2 + 1H3 → 2He4 + 0n1,  if the binding energies of 1H2, 1H3 and 2He4 are respectively, a, b and c (in MeV), then the energy (in MeV) released in this reaction is








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    1H2 and 1H3 requires a and b amount of energies for their nucleons to be separated.
    2He4 releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus. ​
    Hence, Energy released =c – (a + b) = c – a – b

    Correct Option: C

    1H2 and 1H3 requires a and b amount of energies for their nucleons to be separated.
    2He4 releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus. ​
    Hence, Energy released =c – (a + b) = c – a – b

  1. The binding energy of deuteron is 2.2 MeV and that of 2He4 is 28 MeV. If two deuterons are fused to form one 2He4, then the energy released is​​








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    1D2 → 2He4
    Energy released = 28 – 2 × 2.2 = 23.6 MeV
    ​(Binding energy is energy released on formation of Nucleus)

    Correct Option: A

    1D2 → 2He4
    Energy released = 28 – 2 × 2.2 = 23.6 MeV
    ​(Binding energy is energy released on formation of Nucleus)

  1. A nucleus ZXA has mass represented by M(A, Z). If Mp and Mn denote the mass of proton and neutron respectively and B.E. the binding energy in MeV, then








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    The difference in mass of a nucleus and its constituents, ΔM, is called the mass defect and is given by
    ΔM = [ZMp + (A - Z)Mn] - M
    and binding energy = ΔMc2
    [{ZMp + (A - Z)Mn} - M]c2

    Correct Option: A

    The difference in mass of a nucleus and its constituents, ΔM, is called the mass defect and is given by
    ΔM = [ZMp + (A - Z)Mn] - M
    and binding energy = ΔMc2
    [{ZMp + (A - Z)Mn} - M]c2

  1. ​If M (A; Z), Mp and Mn denote the masses of the nucleus ZXA proton and neutron respectively  in units of u ( 1u = 931.5 MeV/c2) and  BE represents its bonding energy in MeV, then








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    Mass defect = ZMp + (A –Z)Mn–M(A,Z)

    or,
    B.E
    c2

    = ZMp + (A–Z) Mn–M(A,Z) ​
    ∴ M (A, Z) = ZMp + (A–Z)Mn –
    B.E
    c2

    Correct Option: A

    Mass defect = ZMp + (A –Z)Mn–M(A,Z)

    or,
    B.E
    c2

    = ZMp + (A–Z) Mn–M(A,Z) ​
    ∴ M (A, Z) = ZMp + (A–Z)Mn –
    B.E
    c2

  1. The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is :








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    Binding energy of two 1H2 nuclei ​
    = 2(1.1 × 2) = 4.4 MeV ​
    Binding energy of one 2He4 nucelus
    ​= 4 × 7.0 =28 MeV ​
    ∴ Energy released
    = 28 – 4.4 = 23.6 MeV

    Correct Option: B

    Binding energy of two 1H2 nuclei ​
    = 2(1.1 × 2) = 4.4 MeV ​
    Binding energy of one 2He4 nucelus
    ​= 4 × 7.0 =28 MeV ​
    ∴ Energy released
    = 28 – 4.4 = 23.6 MeV