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The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is :
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- 30.2 MeV
- 23.6 MeV
- 2.2 MeV
- 28.0 MeV
Correct Option: B
Binding energy of two 1H2 nuclei
= 2(1.1 × 2) = 4.4 MeV
Binding energy of one 2He4 nucelus
= 4 × 7.0 =28 MeV
∴ Energy released
= 28 – 4.4 = 23.6 MeV
