Nuclei

Nuclei

Easy Questions

Modern Physics

Dual Nature of Radiation and Matter
Atoms
Nuclei
Semiconductor Electronics : Materials, Devices and Simple Circuits
  1. ​In the reaction, 1H2 + 1H3 → 2He4 + 0n1,  if the binding energies of 1H2, 1H3 and 2He4 are respectively, a, b and c (in MeV), then the energy (in MeV) released in this reaction is








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    1H2 and 1H3 requires a and b amount of energies for their nucleons to be separated.
    2He4 releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus. ​
    Hence, Energy released =c – (a + b) = c – a – b

    Correct Option: C

    1H2 and 1H3 requires a and b amount of energies for their nucleons to be separated.
    2He4 releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus. ​
    Hence, Energy released =c – (a + b) = c – a – b

  1. ​If M (A; Z), Mp and Mn denote the masses of the nucleus ZXA proton and neutron respectively  in units of u ( 1u = 931.5 MeV/c2) and  BE represents its bonding energy in MeV, then








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    Mass defect = ZMp + (A –Z)Mn–M(A,Z)

    or,
    B.E
    c2

    = ZMp + (A–Z) Mn–M(A,Z) ​
    ∴ M (A, Z) = ZMp + (A–Z)Mn –
    B.E
    c2

    Correct Option: A

    Mass defect = ZMp + (A –Z)Mn–M(A,Z)

    or,
    B.E
    c2

    = ZMp + (A–Z) Mn–M(A,Z) ​
    ∴ M (A, Z) = ZMp + (A–Z)Mn –
    B.E
    c2

  1. A nucleus ZXA has mass represented by M(A, Z). If Mp and Mn denote the mass of proton and neutron respectively and B.E. the binding energy in MeV, then








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    The difference in mass of a nucleus and its constituents, ΔM, is called the mass defect and is given by
    ΔM = [ZMp + (A - Z)Mn] - M
    and binding energy = ΔMc2
    [{ZMp + (A - Z)Mn} - M]c2

    Correct Option: A

    The difference in mass of a nucleus and its constituents, ΔM, is called the mass defect and is given by
    ΔM = [ZMp + (A - Z)Mn] - M
    and binding energy = ΔMc2
    [{ZMp + (A - Z)Mn} - M]c2

  1. The binding energy of deuteron is 2.2 MeV and that of 2He4 is 28 MeV. If two deuterons are fused to form one 2He4, then the energy released is​​








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    1D2 → 2He4
    Energy released = 28 – 2 × 2.2 = 23.6 MeV
    ​(Binding energy is energy released on formation of Nucleus)

    Correct Option: A

    1D2 → 2He4
    Energy released = 28 – 2 × 2.2 = 23.6 MeV
    ​(Binding energy is energy released on formation of Nucleus)

  1. The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV, respectively. When two deuterium nuclei fuse to form a helium nucleus the energy released in the fusion is :








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    Binding energy of two 1H2 nuclei ​
    = 2(1.1 × 2) = 4.4 MeV ​
    Binding energy of one 2He4 nucelus
    ​= 4 × 7.0 =28 MeV ​
    ∴ Energy released
    = 28 – 4.4 = 23.6 MeV

    Correct Option: B

    Binding energy of two 1H2 nuclei ​
    = 2(1.1 × 2) = 4.4 MeV ​
    Binding energy of one 2He4 nucelus
    ​= 4 × 7.0 =28 MeV ​
    ∴ Energy released
    = 28 – 4.4 = 23.6 MeV