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  1. ​In the reaction, 1H2 + 1H32He4 + 0n1,  if the binding energies of 1H2, 1H3 and 2He4 are respectively, a, b and c (in MeV), then the energy (in MeV) released in this reaction is
    1. a + b + c
    2. a + b – c
    3. ​c – a – b ​
    4. ​c + a – b
Correct Option: C

1H2 and 1H3 requires a and b amount of energies for their nucleons to be separated.
2He4 releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus. ​
Hence, Energy released =c – (a + b) = c – a – b



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