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In the reaction, 1H2 + 1H3 → 2He4 + 0n1, if the binding energies of 1H2, 1H3 and 2He4 are respectively, a, b and c (in MeV), then the energy (in MeV) released in this reaction is
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- a + b + c
- a + b – c
- c – a – b
- c + a – b
Correct Option: C
1H2 and 1H3 requires a and b amount of energies for their nucleons to be separated.
2He4 releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus.
Hence, Energy released =c – (a + b) = c – a – b