nuclear fission

Correct Option: A

nuclear fission

₉₃U²³⁵ + ₀n¹ → ₃₈Sr⁹⁰ + ₅₄Xe¹⁴³ + ₀n¹ + energy

Correct Option: A

₉₃U²³⁵ + ₀n¹ → ₃₈Sr⁹⁰ + ₅₄Xe¹⁴³ + ₀n¹ + energy

Binding energy
= 117 × 8.5 + 117 × 8.5 – 236 × 7.6
= 234 × 8.5 – 236 × 7.6
= 1989 – 1793.6 = 200 MeV
Thus, in per fission of Uranium nearly 200 MeV energy is liberated

Correct Option: B

Binding energy
= 117 × 8.5 + 117 × 8.5 – 236 × 7.6
= 234 × 8.5 – 236 × 7.6
= 1989 – 1793.6 = 200 MeV
Thus, in per fission of Uranium nearly 200 MeV energy is liberated

Moderator used in nuclear reactor are graphite and heavy water.

Correct Option: C

Moderator used in nuclear reactor are graphite and heavy water.

Applying principle of energy conservation,
Energy of proton = total B.E. of 2α – energy of Li⁷
= 8 × 7.06 – 7 × 5.6
= 56.48 – 39.2 = 17.28 MeV

Correct Option: D

Applying principle of energy conservation,
Energy of proton = total B.E. of 2α – energy of Li⁷
= 8 × 7.06 – 7 × 5.6
= 56.48 – 39.2 = 17.28 MeV