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If the binding energy per nucleon in 3Li7 and 2He4 nuclei are respectively 5.60 MeV and 7.06 MeV, then the energy of proton in the reaction 3Li7+ p → 2 2He4 is
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- 19.6 MeV
- 2.4 MeV
- 8.4 MeV
- 17.3 MeV
Correct Option: D
Applying principle of energy conservation,
Energy of proton = total B.E. of 2α – energy of Li7
= 8 × 7.06 – 7 × 5.6
= 56.48 – 39.2 = 17.28 MeV
