Nuclei
- If in nuclear fusion process the masses of the fusing nuclei be m1 and m2 and the mass of the resultant nucleus be m3, then
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m3 < (m1 + m2)(∵ m1 + m2 = m3 + E ]
as E = [m1 + m2 – m3] C2Correct Option: D
m3 < (m1 + m2)(∵ m1 + m2 = m3 + E ]
as E = [m1 + m2 – m3] C2
- Fission of nuclei is possible because the binding energy per nucleon in them
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B.E. per nucleon is smaller for lighter as well as heavier nucleus. But fusion reaction occurs for small mass number nuclei and fission reaction occurs for larger mass number nuclei to attain reaction binding energy per nucleon.
Correct Option: D
B.E. per nucleon is smaller for lighter as well as heavier nucleus. But fusion reaction occurs for small mass number nuclei and fission reaction occurs for larger mass number nuclei to attain reaction binding energy per nucleon.
- In any fission process, the ratio
mass of fission products is mass of parent nucleus
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Binding energy per nucleon for fission products is higher relative to Binding energy per nucleon for parent nucleus, i.e., more masses are lost and are obtained as kinetic energy of fission products. So, the given ratio < 1.
Correct Option: C
Binding energy per nucleon for fission products is higher relative to Binding energy per nucleon for parent nucleus, i.e., more masses are lost and are obtained as kinetic energy of fission products. So, the given ratio < 1.
- In the reaction, 1H2 + 1H3 → 2He4 + 0n1, if the binding energies of 1H2, 1H3 and 2He4 are respectively, a, b and c (in MeV), then the energy (in MeV) released in this reaction is
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1H2 and 1H3 requires a and b amount of energies for their nucleons to be separated.
2He4 releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus.
Hence, Energy released =c – (a + b) = c – a – bCorrect Option: C
1H2 and 1H3 requires a and b amount of energies for their nucleons to be separated.
2He4 releases c amount of energy in its formation i.e., in assembling the nucleons as nucleus.
Hence, Energy released =c – (a + b) = c – a – b
- The binding energy of deuteron is 2.2 MeV and that of 2He4 is 28 MeV. If two deuterons are fused to form one 2He4, then the energy released is
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1D2 → 2He4
Energy released = 28 – 2 × 2.2 = 23.6 MeV
(Binding energy is energy released on formation of Nucleus)Correct Option: A
1D2 → 2He4
Energy released = 28 – 2 × 2.2 = 23.6 MeV
(Binding energy is energy released on formation of Nucleus)