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  1. ​If M (A; Z), Mp and Mn denote the masses of the nucleus ZXA proton and neutron respectively  in units of u ( 1u = 931.5 MeV/c2) and  BE represents its bonding energy in MeV, then
    1. M (A, Z) = ZMp + (A – Z) Mn –BE/c2
    2. M (A, Z) = ZMp + ( A–Z) Mn + BE ​
    3. M (A, Z) = ZMp + (A – Z) Mn – BE
    4. M (A, Z) = ZMp + (A – Z)Mn + BE/c2
Correct Option: A

Mass defect = ZMp + (A –Z)Mn–M(A,Z)

or,
B.E
c2

= ZMp + (A–Z) Mn–M(A,Z) ​
∴ M (A, Z) = ZMp + (A–Z)Mn
B.E
c2



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