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					 If M (A; Z), Mp and Mn denote the masses of the nucleus ZXA proton and neutron respectively in units of u ( 1u = 931.5 MeV/c2) and BE represents its bonding energy in MeV, then
 
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- M (A, Z) = ZMp + (A – Z) Mn –BE/c2
 - M (A, Z) = ZMp + ( A–Z) Mn + BE 
 - M (A, Z) = ZMp + (A – Z) Mn – BE
 - M (A, Z) = ZMp + (A – Z)Mn + BE/c2
 
 
Correct Option: A
Mass defect = ZMp + (A –Z)Mn–M(A,Z)
| or, | c2 | 
= ZMp + (A–Z) Mn–M(A,Z) 
| ∴ M (A, Z) = ZMp + (A–Z)Mn – | c2 |