6. The tangential force transmitted (in N) is

1. 1. 3552

   
   
   

   2. 2611

   
   
   

   3. 1776

   
   
   

   4. 1305

   
   
   

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1. View Hint View Answer Discuss in Forum

   P =15 kW
   m = 4 mm
   Z_p = 21
   N = 960 rpm
   b = 25mm
   D_p =mZ_p = 4 × 21 = 84 mm
   

   Speed of pinion, υ =	πDpN	m / s
   	60000

   
   

   = π × 84 ×	960	= 4.22 m / s
   	60000

   
   Also, P = F_tυ
   

   or Ft =		P	=	15 × 1000
   		υ		4.22

   
   ≈ 3552 N

   Correct Option: A

   P =15 kW
   m = 4 mm
   Z_p = 21
   N = 960 rpm
   b = 25mm
   D_p =mZ_p = 4 × 21 = 84 mm
   

   Speed of pinion, υ =	πDpN	m / s
   	60000

   
   

   = π × 84 ×	960	= 4.22 m / s
   	60000

   
   Also, P = F_tυ
   

   or Ft =		P	=	15 × 1000
   		υ		4.22

   
   ≈ 3552 N

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7. A spur pinion of pitch diameter 50 mm rotates at 200 rad/s and transmits 3 kW power. The pressure angle of the tooth of the pinion is 20°. Assuming that only one pair of the teeth is in contact, the total force (in Newton) exerted by a tooth of the pinion on the tooth on a mating gear is ________.

1. 1. 638.5 N.

   
   
   

   2. 637.5 N.

   
   
   

   3. 636.5 N.

   
   
   

   4. 639.5 N.

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: A

   NA

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8. Two mating spur gears have 40 and 120 teeth respectively. The pinion rotates at 1200 rpm and transmits a torque of 20 N.m. The torque transmitted by gear is

1. 1. 6.6 Nm

   
   
   

   2. 20 Nm

   
   
   

   3. 40 Nm

   
   
   

   4. 60 Nm

   
   
   

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1. View Hint View Answer Discuss in Forum

   We know
   

   		Np	=	TG
   		NG		Tp

   
   where,
   N_p = speed of pinion,
   N_G = speed of gear wheel
   T_G = number of teeth of gear,
   T_p = number of teeth of pinion
   

   ∴		1200	=	120
   		NG		40

   
   or N_G =400 r.p.m.
   Since power transmitted by both gear will be equal
   i.e. T_pω_p = T_Gω_G
   where,
   T_p = torque transmited by pinion
   T_G = torque transmitted by gear wheel
   

   ∴		20 × 2π × 1200	=	TG × 2π × 400
   		60		60

   
   ∴ Torque transmitted by gear, T_G = 60 N-m.
   

   Correct Option: D

   We know
   

   		Np	=	TG
   		NG		Tp

   
   where,
   N_p = speed of pinion,
   N_G = speed of gear wheel
   T_G = number of teeth of gear,
   T_p = number of teeth of pinion
   

   ∴		1200	=	120
   		NG		40

   
   or N_G =400 r.p.m.
   Since power transmitted by both gear will be equal
   i.e. T_pω_p = T_Gω_G
   where,
   T_p = torque transmited by pinion
   T_G = torque transmitted by gear wheel
   

   ∴		20 × 2π × 1200	=	TG × 2π × 400
   		60		60

   
   ∴ Torque transmitted by gear, T_G = 60 N-m.
   

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9. A wire rope is designated as 6 x 19 standard hoisting. The numbers 6 × 19 represent

1. 1. diameter in millimeter × length in meter

   
   
   

   2. diameter in centimeter × length in meter

   
   
   

   3. number of strands × number of wires in each strand

   
   
   

   4. number of wires in each Strand × number of strands

   
   
   

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1. View Hint View Answer Discuss in Forum

   NA

   Correct Option: C

   NA

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10. A single-plate clutch has a friction disc with inner and outer radii of 20 mm and 40 mm, respectively. The friction lining in the disc is made in such a way that the coefficient of friction μ varies radially as μ = 0.01 r, where r is in mm. The clutch needs to transmit a friction torque of 18.85 kN mm. As per uniform pressure theory, the pressure (in MPa) on the disc is __________.

1. 1. 0.5 MPa

   
   
   

   2. 0.4 MPa

   
   
   

   3. 0.6 MPa

   
   
   

   4. 1.5 MPa

   
   
   

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1. View Hint View Answer Discuss in Forum

   
   

   Correct Option: A

   
   

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