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The primary and secondary shear loads on bolt P, respectively, are
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- 2 kN, 20 kN
- 20 kN, 2 kN
- 20 kN, 0 kN
- 0 kN, 20 kN
Correct Option: A
Let F1 and F2 resist the 4 kN eccentric load. The primary shear load is due to a direct shear stress of 4kN, which is equally divided amongst the two bolts, i.e. 2 k N,
∴ Fprimary on P = 2 kN
The secondar y load is t o r esist t he moment produced by the eccentric load 4 kN about the C. G. of the joint
Moment M = 4 kN × 2000 mm
= 8000 Nm
Now this moment must be balanced by a moment pr oduced by equal and opposite forces i .e. secondary loads on the bolts
i .e. F × 400 = 800 Nm
⇒ F = 20 kN
