Machine Design Miscellaneous Easy Questions and Answers

As the drum is rotating in anti clock wise direction, T₁ will be right side & T₂ will be clock side.

T₁	= e^μθ = e^{0.25 × π} = 2.19
T₂

⇒ T₂ = = 182.375 N
Braking torque = (T₁ – T₂ )r
= 54.4 N – m

As the drum is rotating in anti clock wise direction, T₁ will be right side & T₂ will be clock side.

T₁	= e^μθ = e^{0.25 × π} = 2.19
T₂

⇒ T₂ = = 182.375 N
Braking torque = (T₁ – T₂ )r
= 54.4 N – m

Given: b = 80 mm = 0.08 m D = 250 mm = 0.25

R =	D	= 0.25
	2

μ = 0.25

θ = 270° = 270 ×	π	= 4.712 radians
	180

F_t = 100 N-m

As	p₁	= e^μθ
	p₂

⇒ p₁ = e^μθ ⋅ p₂ = e^{0.25 × 4.712} ⋅ p₂ = 3.25p₂
Now, F_t = (p₁ − p₂)R

∴ 1000 =		p₁ −	p₁		0.125
			3.25

Solving, we get maximum tension in the belt,
p₁ = 11.56 kN