A force of 400 N is applied to the brake drum of 0.5 m diameter

A force of 400 N is applied to the brake drum of 0.5 m diameter in a band brake system as shown in figure, where the wrapping angle is 180°. If the coefficient of friction between the drum and the band is 0.25, the braking torque applied, in Nm is

As the drum is rotating in anti clock wise direction, T₁ will be right side & T₂ will be clock side.

T₁	= e^μθ = e^{0.25 × π} = 2.19
T₂

⇒ T₂ = = 182.375 N
Braking torque = (T₁ – T₂ )r
= 54.4 N – m

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