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A force of 400 N is applied to the brake drum of 0.5 m diameter in a band brake system as shown in figure, where the wrapping angle is 180°. If the coefficient of friction between the drum and the band is 0.25, the braking torque applied, in Nm is
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- 100.6
- 54.4
- 22.1
- 15.7
Correct Option: B
As the drum is rotating in anti clock wise direction, T1 will be right side & T2 will be clock side.
| = eμθ = e0.25 × π = 2.19 | |
| T2 |
⇒ T2 = = 182.375 N
Braking torque = (T1 – T2 )r
= 54.4 N – m
