31. The bolts in a rigid flanged coupling connecting two shafts transmitting power are subjected to
    

1. 1. shear force and bending moment
      

   
   
   

   2. axial force
      

   
   
   

   3. torsion
      

   
   
   

   4. torsion and bending moment

   
   
   

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   NA

   Correct Option: A

   NA

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32. The bolts in a rigid flanged coupling connecting two shafts transmitting power are subjected to
    

1. 1. shear force and bending moment
      

   
   
   

   2. axial force
      

   
   
   

   3. torsion
      

   
   
   

   4. torsion and bending moment

   
   
   

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   NA

   Correct Option: A

   NA

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33. Stress concentration in a machine component of a ductile material is not so harmful as it is in a brittle material because
    

1. 1. in ductile material local yielding may distribute stress concentration
      

   
   
   

   2. ductile material has larger young's material
      

   
   
   

   3. Poisson's ratio is larger in ductile materials
      

   
   
   

   4. Modulus of rigidity is larger in ductile materials

   
   
   

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   Local yielding reduces stress concentration effect.

   Correct Option: A

   Local yielding reduces stress concentration effect.

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34. In a bolted Joint two smooth members are connected with an axial tightening force of 2200 N. If the bolt used has metric threads of 4 mm pitch, the torque required for achieving the tightening force is
    
    

1. 1. 0.7 Nm
      

   
   
   

   2. 1.0 Nm
      

   
   
   

   3. 1.4 Nm
      

   
   
   

   4. 2.8 Nm
      

   
   
   

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   Tightening force = 2200 N
   Pitch = 4 mm = 0.004 m
   

   Torque = Tightening force ×	0.004	= 1.4 N-m
   	2π

   Correct Option: C

   Tightening force = 2200 N
   Pitch = 4 mm = 0.004 m
   

   Torque = Tightening force ×	0.004	= 1.4 N-m
   	2π

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35. A bolted Joint is shown below. The maximum shear stress, in MPa, in the bolts at A and B, respectively are
    
    

1. 1. 242.6 , 42.5
      

   
   
   

   2. 42.5 , 242.6
      

   
   
   

   3. 42.5 , 42.5
      

   
   
   

   4. 60.15 , 343.64

   
   
   

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   FA = FB = FC =	10	kN
   	3

   
   

   FA =	P.e.r	=	10 × 103 × 150 × 40
   	rA² + rB² + rC²		40² + 0² + 40²

   
   F'_A = 18.75 kN = F'_C
   Shear load at A and C
   F_R = √(F_A)² + (F'_A)² = √(3.33)² + (18.75)²
   F_R = 19.04 KN
   

   τmax =	19.04 × 103
   	(π / 4) × 102

   
   ( τ_max )A,C = 242.5 MPa
   ( τ_max )B = 42.44 MPa
   

   Correct Option: A

   FA = FB = FC =	10	kN
   	3

   
   

   FA =	P.e.r	=	10 × 103 × 150 × 40
   	rA² + rB² + rC²		40² + 0² + 40²

   
   F'_A = 18.75 kN = F'_C
   Shear load at A and C
   F_R = √(F_A)² + (F'_A)² = √(3.33)² + (18.75)²
   F_R = 19.04 KN
   

   τmax =	19.04 × 103
   	(π / 4) × 102

   
   ( τ_max )A,C = 242.5 MPa
   ( τ_max )B = 42.44 MPa
   

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