Machine Design Miscellaneous
- A band brake having bandwidth of 80 mm, drum diameter of 250 mm, coefficient of friction of 0.25 and angle of wrap of 270 degrees is required to exert a friction torque of 1000 N m. The maximum tension (in kN) developed in the band is
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Given: b = 80 mm = 0.08 m D = 250 mm = 0.25
R = D = 0.25 2
μ = 0.25θ = 270° = 270 × π = 4.712 radians 180
Ft = 100 N-mAs p1 = eμθ p2
⇒ p1 = eμθ ⋅ p2 = e0.25 × 4.712 ⋅ p2 = 3.25p2
Now, Ft = (p1 − p2)R∴ 1000 = p1 − p1 0.125 3.25
Solving, we get maximum tension in the belt,
p1 = 11.56 kNCorrect Option: D
Given: b = 80 mm = 0.08 m D = 250 mm = 0.25
R = D = 0.25 2
μ = 0.25θ = 270° = 270 × π = 4.712 radians 180
Ft = 100 N-mAs p1 = eμθ p2
⇒ p1 = eμθ ⋅ p2 = e0.25 × 4.712 ⋅ p2 = 3.25p2
Now, Ft = (p1 − p2)R∴ 1000 = p1 − p1 0.125 3.25
Solving, we get maximum tension in the belt,
p1 = 11.56 kN
- For full depth of involute spur gears, minimum number of teeth of pinion to avoid interference depends upon
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NA
Correct Option: A
NA
- For full depth of involute spur gears, minimum number of teeth of pinion to avoid interference depends upon
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NA
Correct Option: A
NA
- Modern gear tooth profile is given involute shape because
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NA
Correct Option: D
NA
- The basic load rating of a ball bearing is
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NA
Correct Option: B
NA