-- advertisement --

Discussion

  1. Find the sum of cube of first 15 natural numbers.
    1. 15400
    2. 14400
    3. 16800
    4. 13300
  1. Correct Option: B

    Sum of cubes of first n natural numbers = [ n(n+1) ]2
    Given n = 15

    ∴ Required sum = [ ( 15 x 16 ) / 2 ] 2
    = (15 x 8 )2
    = 1202
    = 14400

Your comments will be displayed only after manual approval.

-- advertisement --

Related Topics

 Simplification Fractions Elementary Algebra LCM and HCF Average Approximation Unitary Method Linear Equation Quadratic Equation Discount Surds and Indices Percentage Square root and cube root Order of Magnitude Profit and Loss Odd Man Out and Series Work and Wages Stocks and Shares True Discount Ratio, Proportion Partnership Alligation or Mixture Time and Work Pipes and Cistern Speed, Time and Distance Problem on Trains Height and Distance Banker's Discount Boats and Streams Races and games Problems on Ages Clocks and Calendars Simple interest Compound Interest Sets and Functions Area and Perimeter Volume and Surface Area of Solid Figures Sequences and Series Plane Geometry Logarithm Probability Permutation and Combination Statistics

-- advertisement --