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Two alloys contain tin and iron in the ratio of 1 : 2 and 2 : 3. If the two alloys are mixed in the proportion of 3 : 4 respectively (by weight), the ratio of tin and iron in the newly formed alloy is :
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- 10 : 21
- 13 : 22
- 14 : 25
- 12 : 23
Correct Option: B
Let 3kg of first alloy and 4 kg of second alloy be mixed together.
∴ In 3 kg of mixture,
Tin = 1 kg.
Iron = 2 kg.
In 4 kg of mixture,
| Tin = | × 4 = | = 1.6 kg. | ||
| 5 | 5 |
| Iron = | × 4 = | = 2.4 kg. | ||
| 5 | 5 |
∴ Required ratio
= (1 + 1.6) : (2 + 2.4) = 2.6 : 4.4
= 13 : 22
