A number when divided successively by 4 and 5 leaves remainder

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A number when divided successively by 4 and 5 leaves remainder 1 and 4 respectively.
When it is successively divided by 5 and 4 the respective remainders will be

1. 4, 1
2. 3, 2
3. 2, 3
4. 1, 2

Correct Option: C

According to question ,
The least number X in this case will be determined as follows:
Y = 5 × 1 + 4 = 9

X = 4 × Y + 1 = 4 × 9 + 1 = 37
Now,

Hence, the respective remainders are 2, 3.