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The sum of four numbers is 48. When 5 and 1 are added to the first two; and 3 and 7 are subtracted from the 3rd and 4th, the numbers will be equal. The numbers are
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- 9, 7, 15, 17
- 4, 12, 12, 20
- 5, 11, 13, 19
- 6, 10, 14, 18
Correct Option: D
Let four numbers be a, b, c and d respectively.
∴ a + b + c + d = 48 ......(i)
and,
a + 5 = b + 1 = c – 3 = d – 7 = p (let)
∴ a = p – 5; b = p – 1,
c = p + 3, d = p + 7
From equation (i),
p – 5 + p – 1 + p + 3 + p + 7 = 48
⇒ 4p + 4 = 48
⇒ 4p = 48 – 4 = 44
| ⇒ p = | = 11 | |
| 4 |
⇒ a = p – 5 = 11 – 5 = 6
b = p – 1 = 11 – 1 = 10
c = p + 3 = 11 + 3 = 14
d = p + 7 = 11 + 7 = 18
Therefore , The numbers are 6, 10, 14 and 18 .
