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If the sum of the digits of any integer between 100 and 1000 is subtracted from the same integer, the resulting number is always divisible by
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- 2
- 5
- 6
- 9
- 2
Correct Option: D
A 3–digit number = 100p + 10q + r
Sum of digits = p + q + r
Difference = 100p + 10q + r – p – q – r
Difference = 99p + 9q = 9 (11p + q) i.e. multiple of 9.
Hence required answer is 9 .