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The least number that must be subtracted from 1294 so that the remainder when divided by 9, 11 and 13 will leave in each case the same remainder 6, is :
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- 2
- 3
- 1
- 4
Correct Option: C
LCM of 9, 11 and 13 = 9 × 11 × 13 = 1287
∴ Required lowest number that leaves 6 as remainder = 1287 + 6 = 1293
∴ Required answer = 1294 – 1293 = 1
