The sum of all the 3-digit numbers, each of which on division

Home » Aptitude » Number System » Question

The sum of all the 3-digit numbers, each of which on division by 5 leaves remainder 3, is

1. 180
2. 1550
3. 6995
4. 99090

Correct Option: D

According to the question,
First number = a = 103
Last number = l = 998
∴ If the number of such numbers be n, then,
998 = 103 + (n – 1) × 5
⇒ (n – 1) × 5= 998 – 103 = 895

⇒ n − 1 =	895	= 179
	5

⇒ n = 180

∴ S =	n	(a + 1)
	2

=	180	(103 + 998)
	2

= 90 × 1101 = 99090