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The numbers 1, 3, 5,7 .., 99 and128 are multiplied together. The number of zeros at the end of the product must be :
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- 19
- 22
- 7
- Nil
Correct Option: C
In 2m × 5n, the number of zeros
= n when m ≥ n
= m when m < n
Here, 128 = 27
In 1 × 3 × 5 × 7 × ... × 99 multiples of 5 are 5, 15, 25, 35, 45, 55, 65, 75, 85, 95 (= 510)
Clearly, 7 zeros will be found in the product.
