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					 The difference between two positive numbers is 3. If the sum of their squares is 369, then the sum of the numbers is :
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                        - 81
- 33
- 27
- 25
 
Correct Option: C
Let the number be x and y and x > y.
x – y = 3     ...(i)
x2 +  y2 = 369     ....(ii)
From equation (i)
x – y = 3
⇒  (x – y)2 = 32
⇒  x2 + y2  – 2xy = 9
⇒  = (x2 +  y2) – 9
= 369 – 9 = 360
From equation (ii)
Now,(x2 + y2) = x2 + y2 + 2xy
= 369 + 360 = 729
∴  x + y = √729 = 27
∴  Required sum = 27
 
	