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					 Five times of a positive integer is equal to 3 less than twice the square of that number. The number is
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                        - 3
- 13
- 23
- 33
 
Correct Option: A
Let the positive integer be x.
∴  2x2 – 5x = 3
⇒  2x2 – 3 = 0
⇒  2x2 – 6x + x – 3 = 0
⇒  2x (x – 3) + 1 (x – 3) = 0
⇒  (x – 3) (2x + 1) = 0
| ∴ x = 3 and x = – | |
| 2 | 
is not admissible.
 
	