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Five times of a positive integer is equal to 3 less than twice the square of that number. The number is
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- 3
- 13
- 23
- 33
Correct Option: A
Let the positive integer be x.
∴ 2x2 – 5x = 3
⇒ 2x2 – 3 = 0
⇒ 2x2 – 6x + x – 3 = 0
⇒ 2x (x – 3) + 1 (x – 3) = 0
⇒ (x – 3) (2x + 1) = 0
∴ x = 3 and x = – | |
2 |
is not admissible.